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High or low?
- Craig wanted to buy 3 compact discs which cost $14.49
each. He said the total would be about $45; his sister
Janine said the total would be about $42.
Ignore
taxes.
- How do you think Craig found his estimate? Is his
estimate too high or too low?
- How do you think Janine found her estimate? Is her
estimate too high or too low?
- Try to find a better estimate than Craigs or Janines.
- Donita, Jim, and Annette were thinking about the product of
218 and 93. Answer the following without calculating the
actual product.
- Donita estimated by multiplying 200 by 90. Compare
these numbers to the one in the actual product. Is
Donitas estimate too high or too low?
- Jim estimated by multiplying 220 by 100. Is his
estimate too high or too low?
- Annette first multiplied 200 by 100. She subtracted from
one number and added to the other.
- Which will change the product more, the addition
or the subtraction?
- Is this estimate too high or too low?
- I cant make up my mind, Annette said, so she
multiplied 220 by 90. Is this new estimate too high or
too low?
- Which of the four estimates is closest to the actual
total? Explain your reasoning.
Hints
Hint to problem 1c: How far from the original numbers were the
numbers they used for their estimates?
Hint to problem 2a: How did Donita choose the number she
multiplied?
Hint to problem 2b: How did Jim choose the numbers he
multiplied?
Hint to problem 2c: Consider how much the added or subtracted
number would have been multiplied by, not just how much was
added or subtracted.
Hint to problem 2e: Find the values for the estimates.
If two estimates are low, which one is closer to the actual
product?
Answers
-
- He multiplied 3 by $15. His estimate is too high.
- She multiplied 3 by $14. Her estimate is too low.
- Possible answer: $43.50
-
- Too low
- Too high
-
- The subtraction
- Too low
- Too low
- 20,000. See the solutions for the reasoning.
Solutions
-
- Craig probably multiplied 3 by a number close to 14.49.
Since 45 ÷ 3 = 15, he probably rounded 14.49 up to
15, giving an estimate thats too high.
- Since 42÷3 = 14, Janine probably rounded 14.49 down
to 14, giving an estimate thats too low.
- The actual price, $14.49, is about halfway between the
two numbers used for estimating, 14 and 15. So the
actual total is probably about halfway between their
estimates, around $43.50.
-
- Donita rounded both numbers down to get her factors,
so her estimate will be less than the actual product.
- Jim rounded both numbers up, so his estimate will be
greater than the actual product.
- Annette subtracted 18 from the 218 and added 7 to
the 93. The subtracted 18, when multiplied by 93, is
taking off close to 1,800 from the actual total. The
added 7, when multiplied by the 218, would add more
than 1,400 to the actual total. Annette is subtracting
more than shes adding, and so her estimate is too low.
- Annette added 2 to the 218 and subtracted 3 from the
93. The added 2 would add between 180 and 200 to the
actual total. The subtracted 3 would take off close to
660 from the actual total. Since Annette is subtracting
more than shes adding, her estimate is too low.
- Jims estimate of 22,000 was the only one that was
too high, and Annettes first estimate of 20,000 was
the highest of the underestimates. The closest estimate
must be one of these two. To decide between them,
estimate the error of the estimates.
If
you
have
several
estimates,
the
actual
value
must
be
between
the
lowest
of
the
overestimates
and
the
highest
of
the
underestimates.
By adding 2 to the 218, Jim overestimated by
about 200. (The real increase is 2 × 93, but 200
is close enough.) By adding 7 to the 93, he again
overestimated, this time by 1,400. This makes his
estimate about 1,600 too high.
Annette rounded 218 down to 200, underestimating
by about 1,800. However, she also added 7 to the 93,
overestimating by about 1,400. Overall, she missed by
only about 400, so her estimate is closer.
The
actual
product
is
20,274,
so
Annette
is
off
by
less
than
300.
Annette
got
closer
by
rounding
to
the
nearest
100
than
she
did
by
rounding
to
the
nearest
10.
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